14x^2-24=80x

Solution for 14x^2-24=80x equation:

14x^2-24=80x

We move all terms to the left:

14x^2-24-(80x)=0

a = 14; b = -80; c = -24;
Δ = b2-4ac
Δ = -802-4·14·(-24)
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-88}{2*14}=\frac{-8}{28}
=-2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+88}{2*14}=\frac{168}{28}
=6
$